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	<title>Comments on: The Renaissance Man Uniform Gravitational Acceleration SMACKDOWN</title>
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	<link>http://arcsecond.wordpress.com/2009/10/09/the-renaissance-man-uniform-gravitational-acceleration-smackdown/</link>
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		<title>By: Mark Eichenlaub</title>
		<link>http://arcsecond.wordpress.com/2009/10/09/the-renaissance-man-uniform-gravitational-acceleration-smackdown/#comment-1072</link>
		<dc:creator><![CDATA[Mark Eichenlaub]]></dc:creator>
		<pubDate>Mon, 10 Dec 2012 22:20:13 +0000</pubDate>
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		<description><![CDATA[Kepler would also have been unable to tell you the acceleration of the planets in their orbits.]]></description>
		<content:encoded><![CDATA[<p>Kepler would also have been unable to tell you the acceleration of the planets in their orbits.</p>
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		<title>By: Mark Eichenlaub</title>
		<link>http://arcsecond.wordpress.com/2009/10/09/the-renaissance-man-uniform-gravitational-acceleration-smackdown/#comment-1070</link>
		<dc:creator><![CDATA[Mark Eichenlaub]]></dc:creator>
		<pubDate>Sat, 08 Dec 2012 21:27:39 +0000</pubDate>
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		<description><![CDATA[Peter, you are going to have to study calculus, differential equations, and then mechanics before you can understand the Kepler problem clearly. Ad-hoc algebraic manipulations will not teach you what you want to know.]]></description>
		<content:encoded><![CDATA[<p>Peter, you are going to have to study calculus, differential equations, and then mechanics before you can understand the Kepler problem clearly. Ad-hoc algebraic manipulations will not teach you what you want to know.</p>
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		<title>By: Mark Eichenlaub</title>
		<link>http://arcsecond.wordpress.com/2009/10/09/the-renaissance-man-uniform-gravitational-acceleration-smackdown/#comment-1067</link>
		<dc:creator><![CDATA[Mark Eichenlaub]]></dc:creator>
		<pubDate>Sat, 08 Dec 2012 07:11:14 +0000</pubDate>
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		<description><![CDATA[No, that is not correct. The acceleration of a planet in a Keplerian orbit is always changing, since it points towards the sun and is proportional to 1/r^2.]]></description>
		<content:encoded><![CDATA[<p>No, that is not correct. The acceleration of a planet in a Keplerian orbit is always changing, since it points towards the sun and is proportional to 1/r^2.</p>
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		<title>By: Peter L. Griffiths</title>
		<link>http://arcsecond.wordpress.com/2009/10/09/the-renaissance-man-uniform-gravitational-acceleration-smackdown/#comment-722</link>
		<dc:creator><![CDATA[Peter L. Griffiths]]></dc:creator>
		<pubDate>Tue, 10 May 2011 16:03:45 +0000</pubDate>
		<guid isPermaLink="false">http://arcsecond.wordpress.com/?p=1153#comment-722</guid>
		<description><![CDATA[Further to my comment of 25 April 2011, I hope your readers can tolerate a little bit of algebraic notation, let L equal a small change. From 
v^2=d=1/r which is the usual velocity measure, we have 
v^2+Lv^2=d+Ld=1/(r-Ld).  For the reciprocal velocity measure we have v^2=r=1/d which after the small change will be 
v^2+Lv^2=r+Lr=1/(d-Lr).  This reflects the two ways of measuring velocity, distance per unit time and time per unit distance, one of which is the reciprocal of the other.  Any change of d is equal to the opposite change of r.]]></description>
		<content:encoded><![CDATA[<p>Further to my comment of 25 April 2011, I hope your readers can tolerate a little bit of algebraic notation, let L equal a small change. From<br />
v^2=d=1/r which is the usual velocity measure, we have<br />
v^2+Lv^2=d+Ld=1/(r-Ld).  For the reciprocal velocity measure we have v^2=r=1/d which after the small change will be<br />
v^2+Lv^2=r+Lr=1/(d-Lr).  This reflects the two ways of measuring velocity, distance per unit time and time per unit distance, one of which is the reciprocal of the other.  Any change of d is equal to the opposite change of r.</p>
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		<title>By: Peter L. Griffiths</title>
		<link>http://arcsecond.wordpress.com/2009/10/09/the-renaissance-man-uniform-gravitational-acceleration-smackdown/#comment-701</link>
		<dc:creator><![CDATA[Peter L. Griffiths]]></dc:creator>
		<pubDate>Mon, 25 Apr 2011 15:42:28 +0000</pubDate>
		<guid isPermaLink="false">http://arcsecond.wordpress.com/?p=1153#comment-701</guid>
		<description><![CDATA[One important aspect of Galileo&#039;s law of falling bodies is that this discovery was also made by Kepler in a reciprocal form v^2=1/r where d+r equal the major axis of the elliptical orbit.]]></description>
		<content:encoded><![CDATA[<p>One important aspect of Galileo&#8217;s law of falling bodies is that this discovery was also made by Kepler in a reciprocal form v^2=1/r where d+r equal the major axis of the elliptical orbit.</p>
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		<title>By: Shawn</title>
		<link>http://arcsecond.wordpress.com/2009/10/09/the-renaissance-man-uniform-gravitational-acceleration-smackdown/#comment-341</link>
		<dc:creator><![CDATA[Shawn]]></dc:creator>
		<pubDate>Sun, 29 Nov 2009 05:24:07 +0000</pubDate>
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		<description><![CDATA[Maybe da Vinci was talking about position and triangular numbers rather than velocity. Suppose your position is given by: 0, 5, 20, 45, 80

Triangular Numbers (And Zero)
0, 1, 3, 6, 10, 15, 21, 28...
Average of successive terms
.5, 2, 4.5, 8, 12.5, 18, 24.5
If g=10, multiply by 10 to get the free fall positions
5, 20, 45, 80, 125, ...]]></description>
		<content:encoded><![CDATA[<p>Maybe da Vinci was talking about position and triangular numbers rather than velocity. Suppose your position is given by: 0, 5, 20, 45, 80</p>
<p>Triangular Numbers (And Zero)<br />
0, 1, 3, 6, 10, 15, 21, 28&#8230;<br />
Average of successive terms<br />
.5, 2, 4.5, 8, 12.5, 18, 24.5<br />
If g=10, multiply by 10 to get the free fall positions<br />
5, 20, 45, 80, 125, &#8230;</p>
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		<title>By: &#124; Quiche Moraine</title>
		<link>http://arcsecond.wordpress.com/2009/10/09/the-renaissance-man-uniform-gravitational-acceleration-smackdown/#comment-325</link>
		<dc:creator><![CDATA[&#124; Quiche Moraine]]></dc:creator>
		<pubDate>Fri, 16 Oct 2009 15:13:35 +0000</pubDate>
		<guid isPermaLink="false">http://arcsecond.wordpress.com/?p=1153#comment-325</guid>
		<description><![CDATA[[...] Steel Cage Death Match: da Vinci vs. Galileo in The Renaissance Man Uniform Gravitational Acceleration SMACKDOWN [...]]]></description>
		<content:encoded><![CDATA[<p>[...] Steel Cage Death Match: da Vinci vs. Galileo in The Renaissance Man Uniform Gravitational Acceleration SMACKDOWN [...]</p>
]]></content:encoded>
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		<title>By: Mark Eichenlaub</title>
		<link>http://arcsecond.wordpress.com/2009/10/09/the-renaissance-man-uniform-gravitational-acceleration-smackdown/#comment-322</link>
		<dc:creator><![CDATA[Mark Eichenlaub]]></dc:creator>
		<pubDate>Tue, 13 Oct 2009 10:43:43 +0000</pubDate>
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		<description><![CDATA[According to what I&#039;ve read elsewhere, he was referring to triangular numbers when he mentioned pyramids.  But it does seem like there&#039;s a little room for interpretation, based on the tiny bit of text I have.]]></description>
		<content:encoded><![CDATA[<p>According to what I&#8217;ve read elsewhere, he was referring to triangular numbers when he mentioned pyramids.  But it does seem like there&#8217;s a little room for interpretation, based on the tiny bit of text I have.</p>
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		<title>By: Paul Murray</title>
		<link>http://arcsecond.wordpress.com/2009/10/09/the-renaissance-man-uniform-gravitational-acceleration-smackdown/#comment-321</link>
		<dc:creator><![CDATA[Paul Murray]]></dc:creator>
		<pubDate>Tue, 13 Oct 2009 06:29:13 +0000</pubDate>
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		<description><![CDATA[Pehaps Da Vinci was right? Maybe by &quot;the degree of its descent&quot; he meant the distance, rather than the time? Obviously, that makes his velocity wrong ... unless he meant total average velocity rather than instantaneous velocity?

And a pyramid is three-dimensional, anyway.  The pyramidal numbers increase with the cube of n. Was LdV aware that kinetic energy is proportional to the square of the velocity? Is that what he meant by &quot;the power of it&#039;s motion&quot;?]]></description>
		<content:encoded><![CDATA[<p>Pehaps Da Vinci was right? Maybe by &#8220;the degree of its descent&#8221; he meant the distance, rather than the time? Obviously, that makes his velocity wrong &#8230; unless he meant total average velocity rather than instantaneous velocity?</p>
<p>And a pyramid is three-dimensional, anyway.  The pyramidal numbers increase with the cube of n. Was LdV aware that kinetic energy is proportional to the square of the velocity? Is that what he meant by &#8220;the power of it&#8217;s motion&#8221;?</p>
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